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(F)=-3F^2+2F-3
We move all terms to the left:
(F)-(-3F^2+2F-3)=0
We get rid of parentheses
3F^2-2F+F+3=0
We add all the numbers together, and all the variables
3F^2-1F+3=0
a = 3; b = -1; c = +3;
Δ = b2-4ac
Δ = -12-4·3·3
Δ = -35
Delta is less than zero, so there is no solution for the equation
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